How to Upload/Display Image in Picture Box using OpenFileDialog in c# .net

Introduction:

Browsing and displaying an image in picture box tool using  Windows Forms application is a very simple task. In this application, we use the following classes/controls to do the b.

- OpenFileDialog
- PictureBox
- TextBox
- Button 

Main Functions:

This functions simply perform the following steps:
1. Open a file dialog box so that a user can select an image from his/her machine
2. Browse the image
3. Display selected image in a picture box on a Form
4. Display image file path in text box 

Screen Shot:

Screen 1

Screen 2

Screen 3

Source Code: 

            //Initialize Componets
        public ImageUploadAndPreview()
        {
            InitializeComponent();
        }




        //When Button Click
        private void button1_Click(object sender, EventArgs e)
        {
            // open file dialog
            OpenFileDialog open = new OpenFileDialog();

            // Filter Image
            open.Filter = "Image Files(*.jpg; *.jpeg; *.gif;     *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp";
            if (open.ShowDialog() == DialogResult.OK)
            {
                pbImage.Image = new Bitmap(open.FileName);
                pbImage.SizeMode = PictureBoxSizeMode.StretchImage;
                txtImage.Text = open.FileName;
            }
        } 
 

What is an image filter?

 Image filter is basically a filter that restrict user to select only valid image file. You can remove image filter.  

Download Link

 https://drive.google.com/file/d/0B7XVDU9gdC-lZGRjdENjMGpiNWs/edit?usp=sharing

 If you have any query feel free to comment it will be appreciated :)